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How much antimatter would it take to cause an explosion equal to that of the atomic bomb used on Hiroshima? Please show all work.?

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  • neb
    Lv 7
    5 years ago

    The energy in the Hiroshima bomb was 6.3 x 10^13 joules. Using the equation

    E = mc^2 and solving for m

    m = E/c^2

    Plug in E = 6.3 x 10^13

    Look up c = speed of light

    Calculate m

    You should get an answer of m around .7 grams.

  • Anonymous
    5 years ago

    It's almost impossible. An equivalent of the Hiroshima atomic bomb would take half a gram of antimatter which would take millions of years and $billions of dollars to make.

    According to CERN it's taken them over 30 years to make just 10 billionth of a gram and "A milligram of antimatter will take 100,000 times the annual production rate to produce (or 100,000 years). It will take billions of years for the current production rate to make an equivalent of current typical hydrogen bombs. An equivalent of the Hiroshima atomic bomb will take half a gram of antimatter, but will take two million years"

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