Yahoo Answers is shutting down on 4 May 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

trueprober
Lv 7
trueprober asked in Science & MathematicsMathematics · 8 years ago

1^infinity is easily assumed to be 1. But it is taken under the category of in determinant just as 0/0. Why?

3 Answers

Relevance
  • KevinM
    Lv 7
    8 years ago
    Favourite answer

    Because it depends on how you approach infinity.

    If you approach 0/0 as 0/1, 0/0.1, 0/0.001.... it approaches infinity. If you take it as 1/1, .01/.1, .0001/.01 ... it approaches 0.

    The same with 1^infinity. The limit "e" is known as:

    lim (n->infinity) (1 + 1/n)^n

    This looks like 1^infinity, but it's NOT 1. It's 2.71828....

  • wendalore
    Lv 7
    8 years ago

    Beats the hell out of me, True!

    (I just love that phrase, and never get a chance to use it!)

  • ?
    Lv 7
    8 years ago

    see

    http://mathforum.org/library/drmath/view/56006.htm...

Still have questions? Get answers by asking now.