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How to find the inverse of a diagonal matrix?
Find A^-1 if A =
[alpha, 0, 0]
[0, beta, 0]
[0, 0 , epsilon]
I've looked online and notes that the answer is:
[1/alpha, 0, 0]
[0, 1/beta, 0]
[0, 0, 1/epsilon]
I want to know why. Examples on youtube and my notes do not explain the steps. All they say is that the inverse is 1 over the element.
So whenever I see a diagonal matrix and asked for the inverse, the answer I put down is 1 over the element? I don't have to write any steps to prove that it is because it is stated that it's always 1 over the element.
4 Answers
- zLv 510 years agoFavourite answer
Yes they are right. To verify it, just multiply A and A^(-1) back to see if you get an identity matrix.
- Anonymous6 years ago
This Site Might Help You.
RE:
How to find the inverse of a diagonal matrix?
Find A^-1 if A =
[alpha, 0, 0]
[0, beta, 0]
[0, 0 , epsilon]
I've looked online and notes that the answer is:
[1/alpha, 0, 0]
[0, 1/beta, 0]
[0, 0, 1/epsilon]
I want to know why. Examples on youtube and my notes do not explain the steps. All they say is that the inverse is 1 over...
Source(s): find inverse diagonal matrix: https://biturl.im/hPe5g - Anonymous5 years ago
a = | 2_, -1 | | -1, 2_ | inv a = | 2/3, 1/3 | | 1/3, 2/3 | b = |0 0| |0 0| inverse of 4x4 = [inv a , b ] [b , inv a] = | 2/3, 1/3, 0__, 0__ | | 1/3, 2/3, 0__, 0__ | | 0__, 0__, 2/3, 1/3 | | 0__, 0__, 1/3, 2/3 |