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How to find the inverse of a diagonal matrix?

Find A^-1 if A =

[alpha, 0, 0]

[0, beta, 0]

[0, 0 , epsilon]

I've looked online and notes that the answer is:

[1/alpha, 0, 0]

[0, 1/beta, 0]

[0, 0, 1/epsilon]

I want to know why. Examples on youtube and my notes do not explain the steps. All they say is that the inverse is 1 over the element.

Update:

So whenever I see a diagonal matrix and asked for the inverse, the answer I put down is 1 over the element? I don't have to write any steps to prove that it is because it is stated that it's always 1 over the element.

4 Answers

Relevance
  • z
    Lv 5
    10 years ago
    Favourite answer

    Yes they are right. To verify it, just multiply A and A^(-1) back to see if you get an identity matrix.

  • ?
    Lv 4
    5 years ago

    Inverse Of Diagonal Matrix

  • Anonymous
    6 years ago

    This Site Might Help You.

    RE:

    How to find the inverse of a diagonal matrix?

    Find A^-1 if A =

    [alpha, 0, 0]

    [0, beta, 0]

    [0, 0 , epsilon]

    I've looked online and notes that the answer is:

    [1/alpha, 0, 0]

    [0, 1/beta, 0]

    [0, 0, 1/epsilon]

    I want to know why. Examples on youtube and my notes do not explain the steps. All they say is that the inverse is 1 over...

    Source(s): find inverse diagonal matrix: https://biturl.im/hPe5g
  • Anonymous
    5 years ago

    a = | 2_, -1 | | -1, 2_ | inv a = | 2/3, 1/3 | | 1/3, 2/3 | b = |0 0| |0 0| inverse of 4x4 = [inv a , b ] [b , inv a] = | 2/3, 1/3, 0__, 0__ | | 1/3, 2/3, 0__, 0__ | | 0__, 0__, 2/3, 1/3 | | 0__, 0__, 1/3, 2/3 |

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