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tuhinrao

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  • 'n', 'Y' are real. If n/ln(n)=Y, for a given Y what is n?

    Tried a lot of equatons and lot of webpages but to no avail.

    The graph shows that there will be 2 values of n for every Y.

    If a and b are the 2 values of n then 1 < a < e and e < b

    When Y is minimum, Y=1. at that point a=b=e.

    Other relations I found from above are:

    a^b=b^a

    a^(1/a)=b^1/b)

    But these are of no use in finding 'a' if 'b' is given or vica versa.

    So what is n in terms of Y explicitly? Is there a relation between a and b, such that knowing 'a', 'b' can be found out?

    1 AnswerMathematics9 years ago
  • How does one tune the Piano?

    I am not a tuner, but have a piano and currently learing diploma repertoire. I have a nag of Physics and acoustics and like to know how things work. I have seen the pianotuner come and tune my upright piano, how does he do that?

    4 AnswersMusic1 decade ago